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dooboose15
27.11.2019 •
Mathematics
Sam did 480 j of work when moving a bag with a mass of 38 kg. he did the work in 4 minutes. what was the power output?
a.442 w
b.20 w
c.120 w
d.2 w
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Ответ:
Option D is the correct answer.
Step-by-step explanation:
We have expression for power,
Work done, W = 480 J
Time taken, t = 4 minutes = 4 x 60 = 240 seconds.
Option D is the correct answer.
Ответ:
The time time for the Acorn to descends from 13 feet to 1 feet is 52.25 seconds
Step-by-step explanation:
Given as :
The initial height of acorn = 13 feet in air
The rate of its descends = r = 4.8 feet every seconds
The final height of acorn = 1 feet
Le the time period of its descends = t sec
According to question
final height of acorn after t sec= initial height of acorn ×![(1-\dfrac{rate}{100})^{\textrm time}](/tpl/images/0416/3651/5d0fa.png)
Or, 1 feet = 13 feet ×![(1-\dfrac{r}{100})^{\textrm t}](/tpl/images/0416/3651/714c4.png)
Or, 1 feet = 13 feet ×![(1-\dfrac{4.8}{100})^{\textrm t}](/tpl/images/0416/3651/17689.png)
Or,
= ![(0.952)^{\textrm t}](/tpl/images/0416/3651/fdfae.png)
Or, 0.07693 =![(0.952)^{\textrm t}](/tpl/images/0416/3651/fdfae.png)
Taking log both side
Log 0.07693 = Log (
)
or, - 1.113 = t Log (0.952) ( from log property
)
Or, - 1.113 = t ( - 0.0213 )
∴ t =![\dfrac{1.113}{0.0213}](/tpl/images/0416/3651/59596.png)
I.e t = 52.25 sec
So , The descending time is t = 52.25 seconds
Hence The time time for the Acorn to descends from 13 feet to 1 feet is 52.25 seconds Answer