caroline1390
24.07.2020 •
Mathematics
SB
Compare the process of solving
|x - 11 +1 < 15 to that of solving
|x - 11 +1 > 15.
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Ответ:
x = 0
Step-by-step explanation:
i) x - 11 + 1 < 15
x - 10 < 15
x < 10 + 15
x < 25
ii) x - 11 + 1 > 15
x - 10 > 15
x > 25
Therefore to compare (i) and (ii)
25 < x < 25
In any case, x = 0
Ответ:
3b^2(a^1c-3c+4^3)