Scores on the Wechsler intelligence quotient (IQ) test for adults have a normal probability distribution with a mean score of 100 and a standard deviation of 15 points. The US military has minimum enlistment standards at about an IQ score of 85. Based on IQ scores only, what is the probability that a randomly selected adult does not meet US military enlistment standards

Probability = 0.1587

Step-by-step explanation:

The provided information is:

Let X be the scores of the IQ test for adults that is normally distributed with mean = 100 and standard deviation = 15.

Also, US military has minimum IQ score of 85.

Thus, the probability that randomly selected adult does not meet US military enlistment standards is:

The probability can also be written as:

Thus,

Using the Normal probability table probability of Z = -1 is 0.1587

Thus, the required probability is 0.1587

y = - 2x + 7/6

Step-by-step explanation:

The point slope form of the equation is expressed as

y - 2/3 = - 2(x - 1/4)

Comparing with the point slope form of an equation,

y - 1 = m(x - 1)

From the given equation,

Slope, m= - 2

The point through which the line passes through is ( 1/4 , 2/3)

The slope intercept form is expressed as

y = mx + c

Where

m represents slope

c represents intercept

To determine c, we we would substitute m = - 2, x = 1/4 and y = 2/3 into y = mx + c. It becomes

2/3 = - 2 × 1/4 + c

2/3 = - 1/2 + c

c = 2/3 + 1/2 = 7/6

Therefore, the slope intercept form would be

y = - 2x + 7/6