jj1077348

10.11.2020 • 

Mathematics

Scoring a hole-in-one is the single greatest shot a golfer can make. In the 1989 U.S. Open, four players each made holes-in-one on the sixth hole at Oak Hill Country Club. Golf Digest (1990) reports that the estimated probability of making a hole-in-one is approximately 12,780 for a professional golfer. What is the probability that these four players each make a hole-in-one on the sixth hole during the same round? What assumption do we have to make? What is the probability that none of these golfers makes a hole-in-one on the sixth hole? What is the probability that at least one of these golfers makes a hole-in-one on the sixth hole?

Ответ:

expeditionofsin

10.12.2020

Mathematics

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Omg that’s so much to read

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Ответ:

lackin2056

11.04.2021

Mathematics

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$106

Step-by-step explanation:

So, this is what we know:

$6 per vehicle (1 bus) + $2 per person (50 people)

Here is the solution:

= $6 + $100

= $106

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