kat9940
30.09.2019 •
Mathematics
Scuba diver dove from the surface of the ocean to an elevation of -89 9/10 feet at a rate of -24 ft./min. after spending 11 minutes at that elevation the diver ascended to an elevation of -18 9/10 feet the total time for the dive so far was 18 1/8 minutes. what was the rate of change in the divers elevation during the ascent round your answer to the nearest hundredth
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Ответ:
A). interval 0 ≤ x ≤ 2
B). interval 2 ≤ x ≤ 4
C). interval 8 ≤ x ≤ 10
D). h(14) = 0
Step-by-step explanation:
Part A.
In the interval 0 ≤ x ≤ 2, height of the water balloon is increasing.
Part B.
In the interval 2 ≤ x ≤ 4, height of the water balloon is constant.
Part C.
In the interval 8 ≤ x ≤ 10, height of the water balloon is decreasing the fastest.
Slope of the line between x = 8 and x = 10 is the maximum.
Part D.
Since at x = 10 height of the water balloon is h = 0, therefore, at any moment after x = 10 seconds height of the balloon will remain zero.