Mathematics: See attached picture

See attached picture - id11355986, andrewsaul04

makayladurham19

24.03.2021

$\frac{f(x+h)-f(x)}{h}$ =2x - h

Step-by-step explanation:

Given

f(x) = 8 - x^2

Required

Determine: $\frac{f(x+h)-f(x)}{h}$

First, we calculate f(x + h)

f(x) = 8 - x^2

f(x+h) = 8 - (x+h)^2

f(x+h) =8- x^2-2xh-h^2

So, we have:

$\frac{f(x+h)-f(x)}{h}$ $= \frac{8- x^2-2xh-h^2 - 8 + x^2}{h}$

$\frac{f(x+h)-f(x)}{h}$ $= \frac{8 - 8 + x^2- x^2-2xh-h^2}{h}$

$\frac{f(x+h)-f(x)}{h}$ $= \frac{-2xh-h^2}{h}$

$\frac{f(x+h)-f(x)}{h}$ =2x - h

0,0(0 оценок)