Mathematics: Select the two values of x that are roots of this equation 2x-3=-5x^2

4(2+3c)=568+12c=56-8 -812c=48/12 /12c=4...

Select the two values of x that are roots of this

Timsters333

07.01.2022

The roots are -1 and 0.60

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x-3=-5x^{2}$

$5x^{2}+2x-3=0$

$a=5\\b=2\\c=-3$

substitute in the formula

$x=\frac{-2(+/-)\sqrt{2^{2}-4(5)(-3)}} {2(5)}$

$x=\frac{-2(+/-)\sqrt{64}} {10}$

$x=\frac{-2(+/-)8} {10}$

$x=\frac{-2(+)8} {10}=0.60$

$x=\frac{-2(-)8} {10}=-1$

therefore

The roots are -1 and 0.60

0,0(0 оценок)