Seun, tayo and dayo are to share n120 in the ratio 4: 3: 2 respectively. what is the sum of the shares of seun and dayo?

By using the given ratio, we will see that the sum of the shares of Seun and Dayo is N80.

How to use the ratio to find how much each one gets?

We know that the 3 kids want to share N120 in a ratio of 4:3:2

To know how much each kid gets, we first need to add the 3 numbers of the ratio.

4 + 3 + 2 = 9

Now we divide the thing that they want to divide by that number:

N120/9 = N13.33...

Now, using the ratio again, we multiplicate the above quotient by the correspondent value for each one.

Seun gets 4 times that: 4*N13.33... = N53.33...Tayo gets 3 times that: 3*N13.33... = N40Dayo gets 2 times that: 2*N13.33... = N26.66...

Then the sum of the shares of Seun and Dayo is:

N53.33... + N26.66... = N80

If you want to learn more about ratios, you can read:

link

The total whole number area of the square = 1.

Part A + Part B + Part C = 1.

1/3  +  2/5 + C  = 1.

(5+ 6)/15 +    C  = 1.    LCM of 3 and 5 is 15.

11/15 + C = 1.

C =  1/1 - 11/15   = (15 -11)/15

C = 4/15.

Cheers.