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roro2599
21.10.2019 •
Mathematics
Show that a = −1 + √3i and b = 2 satisfy 1/a+b=1/a + 1/b
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Ответ:
LHS =
= RHS = ![\frac{1 - \sqrt3i}{4}](/tpl/images/0338/6288/3e94f.png)
Step-by-step explanation:
Data provided in the question:
a = −1 + √3i and b = 2
to prove:
Considering the LHS
⇒![\frac{1}{a+b}](/tpl/images/0338/6288/96d11.png)
substituting the value of a and b, we get
⇒![\frac{1}{−1 + \sqrt3i+2}](/tpl/images/0338/6288/12259.png)
or
⇒![\frac{1}{1 + \sqrt3i}](/tpl/images/0338/6288/8879d.png)
on multiplying and dividing by conjugate ( 1 - √3i )
we get
or
or
or
Now,
considering the RHS
substituting the value of a and b, we get
⇒![\frac{1}{-1 + \sqrt3i} + \frac{1}{2}](/tpl/images/0338/6288/2603c.png)
or
⇒![\frac{2\times1 + ( -1 + \sqrt3i)\times1}{(-1 + \sqrt3i)\times2}](/tpl/images/0338/6288/ed415.png)
or
⇒![\frac{2 + ( -1 + \sqrt3i)}{(-1 + \sqrt3i)\times2}](/tpl/images/0338/6288/bd6f7.png)
or
⇒![\frac{1 + \sqrt3i}{(-1 + \sqrt3i)\times2}](/tpl/images/0338/6288/9eb78.png)
now,
on multiplying and dividing by conjugate ( -1 - √3i )
we get
or
or
or
or
or
or
or
Since, LHS = RHS
hence satisfied
Ответ:
the answer should be x=0