Simplify"
2x² + 16x + 14 / X² - 1​

 16x+3+x214​

Step-by-step explanation:

Multiply 2 and 2 to get 4.

4+16x+x214​−1

Subtract 1 from 4 to get 3.

3+16x+x214​

To add or subtract expressions, expand them to make their denominators the same. Multiply 3+16x times x2x2​.

x2(3+16x)x2​+x214​

Since x2(3+16x)x2​ and x214​ have the same denominator, add them by adding their numerators.

x2(3+16x)x2+14​

Do the multiplications in (3+16x)x2+14.

x23x2+16x3+14​

Answer with explanation

Data Set A: 2,9,9,2,5,6,4

Data Set B: 7,1,6,9,0,2,0

Data Set C: 9,2,4,8,3,7,1

Data Set D: 2,3,5,9,4,9,1

Mean of a data set

Mean of Data set A=

Mean of Data set B=

Mean of Data set C=

Mean of Data set D=

→Modulus of Difference between Mean and variate in data set A

  <p> ⇒ Mean, of Deviation taken from Mean of data set A</p><p> [tex]=\frac{114}{49}" class="latex-formula" id="TexFormula6" src="https://tex.z-dn.net/?f=%3D%7B%5Cfrac%7B23%7D%7B7%7D%2C%5Cfrac%7B26%7D%7B7%7D%2C%5Cfrac%7B26%7D%7B7%7D%2C%5Cfrac%7B23%7D%7B7%7D%2C%5Cfrac%7B2%7D%7B7%7D%2C%5Cfrac%7B5%7D%7B7%7D%2C%5Cfrac%7B9%7D%7B7%7D%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%20%E2%87%92%20Mean%2C%20of%20Deviation%20taken%20from%20Mean%20of%20data%20set%20A%3C%2Fp%3E%3Cp%3E%20%20%20%20%20%20%20%20%5Btex%5D%3D%5Cfrac%7B114%7D%7B49%7D" title="={\frac{23}{7},\frac{26}{7},\frac{26}{7},\frac{23}{7},\frac{2}{7},\frac{5}{7},\frac{9}{7}}[\tex]</p><p> ⇒ Mean, of Deviation taken from Mean of data set A</p><p> [tex]=\frac{114}{49}">

        =2.33 (approx)→MAD

→Modulus of Difference between Mean and variate in data set B

          =3.43 (approx)→MAD

→Modulus of Difference between Mean and variate in data set C

  <p> ⇒ Mean, of Deviation taken from Mean of data set C</p><p> [tex]=\frac{132}{49}" class="latex-formula" id="TexFormula8" src="https://tex.z-dn.net/?f=%3D%7B%5Cfrac%7B29%7D%7B7%7D%2C%5Cfrac%7B20%7D%7B7%7D%2C%5Cfrac%7B6%7D%7B7%7D%2C%5Cfrac%7B22%7D%7B7%7D%2C%5Cfrac%7B13%7D%7B7%7D%2C%5Cfrac%7B15%7D%7B7%7D%2C%5Cfrac%7B27%7D%7B7%7D%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%20%20%E2%87%92%20Mean%2C%20of%20Deviation%20taken%20from%20Mean%20of%20data%20set%20C%3C%2Fp%3E%3Cp%3E%20%20%20%20%20%20%20%20%5Btex%5D%3D%5Cfrac%7B132%7D%7B49%7D" title="={\frac{29}{7},\frac{20}{7},\frac{6}{7},\frac{22}{7},\frac{13}{7},\frac{15}{7},\frac{27}{7}}[\tex]</p><p> ⇒ Mean, of Deviation taken from Mean of data set C</p><p> [tex]=\frac{132}{49}">

          =2.70(approx)→MAD

→Modulus of Difference between Mean and variate in data set D

         =2.53 (approx)→MAD

→Data Set B, has maximum Mean Absolute Deviation,among four data sets,which will be helpful in determining ,the variation.

Option B: Data Set ,B:→ {7,1,6,9,0,2,0} ,mean absolute deviation (MAD) is a good indicator of variation of the data.