Simplify 2x + 7 / 2x^4 + 21x^3 + 35x^2 - 37x + 46

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A set containing 10 elements can have subsets which will contain 1 element, 3 elements, 5 elements, 7 elements, and 9 elements. The numbers enumerated are all odd numbers. Counting, we can conclude that a set containing 10 elements will have 5 subsets which will contain odd number of elements.