Mathematics: Simplify (b^9)^3 a.b^24 b.b^6 c.b^27 d.b^9

Simplify (b^9)^3 a.b^24 b.b^6 c.b^27 d.b^9 - id93246279257771, tracitalbot

Ответ:

beevus2666

10.03.2022

Mathematics

C. b^27

Step-by-step explanation:

By the definition of exponents

(b^9)^3=b^9*b^9*b^9

And since for any real numbers r,x, and

$r^x*r^y=r^{(x+y)}$

This makes

$(b^9)^3=b^9*b^9*b^9=b^{{9+9+9}}=\boxed{b^{27}}$

Which is choice C.

Alternatively, we could use the identity

$(r^x)^y=r^{xy}$

in which case

$(b^9)^3=b^{(9*3)}= \boxed{b^{27}}$

which is the same answer.

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Ответ:

marknjenbennetp3j1v1

04.01.2021

Mathematics

First, we need to solve for the common ratio from the data given by using the equation.

a(n) = a(1) r^(n-1)
15 = -3 r^(2-1)
-5 = r
r = -5

Then, we can find the sum by the expression:

S(n) = a(1) ( 1 - r^n) / 1-r
S(8) = -3 (1 + 5^8) / 1+5
S(8) = -195313

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Simplify (b^9)^3 a.b^24 b.b^6 c.b^27 d.b^9

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