Mathematics: Simplify each expression. 3a^2b^-4/12a^-2b-2 a. a^4/4b^2 b.1/4b^6 c.1/4a^-4b^2 d.a^4/4b^6 second question is v^3w^-3/-v^-6w^3 a.-1/-v^3 b.-v^9/-w^6 c.1/v^3 -v^9w^-6 i needyou very muuuch

Yes. It s a quadratic function....

Simplify each expression. 3a^2b^-4/12a^-2b-2 a. a^4/4b^2

Ответ:

Masonb1849

15.03.2022

Mathematics

1) A. a^4/4b^2

2) -v^9w^-6

Step-by-step explanation:

given

3a^2b^-4/12a^-2b-2

$\frac{3a^2b^{-4}}{12a^{-2}b^{-2}}\\\\$

canceling common factor 3, we get

$\frac{a^2b^{-4}}{4a^{-2}b^{-2}}$

$=\frac{b^{-4}a^{2-\left(-2\right)}}{4b^{-2}}$ $=\frac{b^{-4}a^{2-\left(-2\right)}}{4b^{-2}}$

$=\frac{a^4}{4b^{-2-\left(-4\right)}}$

$=\frac{a^4}{4b^2}$

Given:

v^3w^-3/-v^-6w^3

$=-\frac{v^3w^{-3}}{v^{-6}w^3}\\=\frac{w^{-3}v^{3-\left(-6\right)}}{w^3}\\=\frac{v^9w^{-3}}{w^3}\\=\frac{v^9}{w^{3-\left(-3\right)}}\\=-\frac{v^9}{w^6}\\$

=-v^9w^-6 !

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Simplify each expression. 3a^2b^-4/12a^-2b-2
a. a^4/4b^2
b.1/4b^6
c.1/4a^-4b^2
d.a^4/4b^6
second question is
v^3w^-3/-v^-6w^3
a.-1/-v^3
b.-v^9/-w^6
c.1/v^3
-v^9w^-6
i needyou very muuuch

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