Solve 2|x| = 3

a. {-3/2, 3/2}
b. {-1, 1}
c. {-2/3, 2/3}

The Absolute Value: 2|x| ---> 3

Look for the Absolute Value in the equality that we have found (entered) 2|x| ---> 3

Your first term: 2|x|

If you had a negative term: -2×(x)

But, if youre working with the positive term then it would be: +2×(x)


Now, 2 × x > 3

The value of 'x' becomes a negative

So, -x = 3 over the number 2 ( 3 / 2 <--- this is what I am talking about if in case you don't get what I am saying )

Since you don't have anything else ... lets make a -1 from each other of your sides

the fraction becomes negative as well

x = 3 / 2

2[x] > 3

2 [x] ---> 3

If we divide by the number 2 we get the value of x as > 3 / 2


For the first one: 3 / 2

For the second one: -3 / 2

Therefore we finally get to your result, which is: ✅A: [-3 / 2 , 3 / 2} ✅

First find the radius by taking half the diameter. Use the radius to find the base area by using the formula for the area of a circle. Find the product of the base area and height, and then take one-third of the product.