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brien301
19.08.2019 •
Mathematics
Solve 2cos^2x + cosx − 1 = 0 for x over the interval [0, 2 pi ).
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Ответ:
This could also be written as, where
This would factorize to give:
So we can factorize our original expression:
We can then solve for
And also:
So our values for
As:
Our final solutions for
Ответ:
(cosx+1)(2cosx-1)=0
so cosx+1=0
or 2cosx-1=0
1) cosx+1=0
cosx=-1
x=π+2πk, k∈Z
2) 2cosx-1=0
2cosx=1
cosx=0.5
x=+-
find value for the interval [0, 2 pi )
{
Ответ: