Solve 2x2 – 3x = 12 using the quadratic formula.

Quadratic Formula: (-b +/- sqrt(b^2 - 4ac)) / 2a

2x^2 - 3x = 12

2x^2 - 3x - 12 = 0

a = 2

b = -3

c = -12

(--3 +/- sqrt( (-3)^2 - 4(2)(-12) )) / 2(2)

3 +/- sqrt( 9 + 96 ) / 4

3 +/- sqrt(105) / 4

Answers: ,

Hope this helps!

The midpoint of the horizontal line segment (-6, 3) (10, 3) is (2, 3)

Step-by-step explanation:

The midpoint formula: (x1+x2)/2 ,  (y1+y2)/2

(-6+10)/2 ,  (3+3)/2

4/2 , 6/2

2, 3