Solve: 3 + Vx+ 2 = 11
62
64
O{ }

D.HJ = 25, JK = 25, HK = 50.

Step-by-step explanation:

Given  : J is the midpoint of HK¯¯¯¯¯¯¯ .  and HK and Measure of segment HJ is 9x-2 and that of segment JK is 4x+13.

To find :  What are HJ, JK, and HK.

Solution ; We have given that J is the midpoint of HK

HJ = 9x-2 .

JK  = 4x+13.

Midpoint :  point that divide the line in to two equally parts.

Then

HJ = Jk

9x-2 = 4x+13 .

On subtracting 4x from both sides

9x -4x -2 = 13

5x - 2 = 13.

On adding by 2 both sides

5x = 15

On dividing both sides bu 5

x = 3.

Then HJ = 9 (3) - 2

HJ = 27 - 2 = 25

HJ =  25 .

JK = 4 ( 3) + 13

JK = 12 + 13 = 25 .

Jk = 25 .

HK = HJ + Jk .

HK = 25 + 25.

HK = 50.

Therefore, D.HJ = 25, JK = 25, HK = 50.