Solve |3x - 4| = 15
a) {-19/3, 19/3}
b) {11/3, 19/3}
c) {-11/3, 19/3}

option C

{-11/3 , 19/3}

Step-by-step explanation:

Given in the question an equation

|3x-4| = 15

To solve the absolute equation we need to add ± on right side of equation.

3x-4 = ±15

3x = 15+4 or 3x = -15 + 4

3x = 19  or  3x = -11

x = 19/3  or  x = -11/3

The solution of |3x-4| = 15 is {-11/3 , 19/3}

The solution of I3x - 4I = 15 is {-11/3 , 19/3}

Step-by-step explanation:

* Lets explain the meaning of I I (absolute value)

- The absolute value of any number is the magnitude of the number

means the value of the number without its sign, we ignore the sign

of the number

- The absolute never equal a negative value

- If IxI = a, then x = a or x = -a

* Now lets solve the problem

∵ I3x - 4I = 15

∴ 3x - 4 = 15 OR 3x - 4 = -15

* Lets solve the two equation

∵ 3x - 4 = 15 ⇒ add 4 to both sides

∴ 3x = 19 ⇒ divide both sides by 3

∴ x = 19/3

∵ 3x - 4 = -15 ⇒ add 4 to both sides

∴ 3x = -11 ⇒ divide each side by 3

∴ x = -11/3

* The solution of I3x - 4I = 15 is {-11/3 , 19/3}

a. Jada got the measurement 16m.

b. The measured depth differ 0.2m from the actual depth.

c. There is a 12.66% error in calculation.

Step-by-step explanation:

Given,

The depth of lake = 15.8 m

a. Jada accurately measured the depth of the lake to the nearest meter. What measurement did Jada get

When a digit after the decimal point is 5 or more than that, the number before decimal is rounded to the next number.

Therefore,

15.8 rounded to nearest number is 16.

The depth of lake measured by Jada = 16 m

Jada got the measurement 16m.

b. By how many meters does the measured depth differ from the actual depth?

Difference = Approx - Exact

Difference = 16 - 15.8 = 0.2m

The measured depth differ 0.2m from the actual depth.

c. Express the measurement error ad a percentage of the actual depth.