Solve 6 - 2/3(x+5)=4x algebraically

4/7 =x

Step-by-step explanation:

6 - 2/3(x+5)=4x

Multiply each side by 3 to clear the fraction

3(6 - 2/3(x+5))=4x*3

Distribute

18 -2(x+5) =12x

Distribute the 2

18 -2x-10 = 12x

Combine like terms

8 -2x = 12x

Add 2x to each side

8-2x+2x =12x+2x

8 = 14x

Divide by 14 on each side

8/14 =14x/14

4/7 =x

I'm assuming you are asking if the above statements are true or false

All true

Step-by-step explanation:

In the first statement, an equation may have different numbers on both sides of the equation after solving the equation such that we have 0=5 for instance given 1x=1x+5. This means that we cannot solve this equation and it cannot be true

In the second statement, an equation may be infinite meaning that is true for all values for the variables such that we have equal numbers on both sides of the equation 1=1, 4=4,0=0 for instance given equations like x−10+x=8+2x−18

In last statement, an equation is true if the variable equals a number meaning that the equation has one solution such as x=2 given an equation like 2x+4=8