MajentaSnow66
08.01.2020 •
Mathematics
Solve by using
the quadratic formula
1) 2x² = 3x+14
2) 6x²-20=26x
3 )9x²+6x-8=0
4) 2x² + 13x+15=0
5) 2 x²+7x+6=0
6) 4x²+8x+3=0
7) x² + 3x-28=0
8) x ²-9=0
9) 5x²+10x=0
10) x² -x-12 = 0
(11) 12 x² + 7x + 1 =0 12)10x²+13x=30
Solved
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Ответ:
1) x=-2 or x=7/2
2) x=-2/3 or x=5
3) x=-4/3 or x=2/3
4) x=-5 or x=-3/2
5) x=-2 or x=-3/2
6) x= -3/2 or x=-1/2
7) x= -7 or x=4
8) x= -3 or x=3
9) x=-2 or x=0
10) x= -3 or x=4
11) x= -1/3 or x=-1/4
12) x= -5/2 or x= 6/5
Ответ:
x=0, y=15
Step-by-step explanation:
x/2+y/5=3
(5x+2y)/10=3
5x+2y=30
2y=30-5x
y=(30-5x)/2....(1)
we know, 5x+2y=30
substituting (1)
5x+2×
=30
5x+30-5x=30
5x-5x=1
x=0
y= (30-5x)/2= 30/2=15
let's check the answer,
0/2+15/5=3
15/5=3
3=3
LHS=RHS