Mathematics: Solve each equation 1) log5-log2x=1 2) 2log(x+1)=5

Solve each equation 1) log5-log2x=1 2) 2log(x+1)=5 - id152122151776329, sophialoperx

Ответ:

Babygirljay1540

30.12.2021

$1)\\log5-log2x=1;\ D:x 0\\\\log(5:2x)=log10\\\\log\frac{5}{2x}=log10\iff\frac{5}{2x}=10\\\\20x=5\ \ \ /:20\\\\x=\frac{1}{4}\in D$

$2)\\2log(x+1)=5;\ D:x+1 0\to x -1\\\\log(x+1)^2=log10^5\iff(x+1)^2=10^5\\\\x+1=-\sqrt{10^5}\ \vee\ x+1=\sqrt{10^5}\\\\x+1=-\sqrt{10^4\cdot10}\ \vee\ x+1=\sqrt{10^4\cdot10}\\\\x=-100\sqrt{10}-1\notin D\ \vee\ x=100\sqrt{10}-1\in D$

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Ответ:

terryg4397

07.03.2022

Mathematics

the answer is B

Step-by-step explanation:

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Solve each equation 1) log5-log2x=1 2) 2log(x+1)=5

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