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Lilbre6999
15.01.2020 •
Mathematics
Solve equation algebraically 3 root x-2x=-5
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Ответ:
Step-by-step explanation:
Given linear equation as :
3
- 2 x = - 5
Rearranging the equation
3
= 2 x - 5
Taking square both side
Or, 9 x = 4 x² - 20 x + 25 [ from (a + b)² = a² + 2ab + b² ]
Or, 4 x² - 20 x - 9 x + 25 = 0
Or, 4 x² - 29 x + 25 = 0
The equation is in the form of quadratic equation i.e a x² + b x + c = 0
So, x =![\frac{- b\pm \sqrt{b^{2} - 4\times a\times c}}{2\times a}](/tpl/images/0455/5909/d471f.png)
Or, x =![\frac{- (-29)\pm \sqrt{(-29)^{2} - 4\times 4\times 25}}{2\times 4}](/tpl/images/0455/5909/f665c.png)
Or, x =![\frac{- 29\pm \sqrt{841 - 400}}{8}](/tpl/images/0455/5909/c6c03.png)
Or, x =![\frac{- 29\pm \sqrt{441}}{8}](/tpl/images/0455/5909/a5b14.png)
Or, x =
, ![\frac{-29-21}{8}](/tpl/images/0455/5909/24448.png)
Or, x = - 1 , - 6.25
So, The value s of x = - 1 , - 6.25
Hence, The value of x is - 1 , - 6.25 Answer
Ответ:
~![\frak{Amphitrite1040:}](/tpl/images/1235/0101/ece51.png)