Mathematics: Solve for all possible values of x. square root of the quantity x minus 8 end quantity minus 3 equals 1

Solve for all possible values of x. square root of

Ответ:

nadiarose6366

05.01.2022

x = 24

Step-by-step explanation:

In a radical equation it is critical to start by isolating the root that contains the unknown on one side of the equal sign, so we do such by adding 3 to both sides:

$\sqrt{x-8} -3 = 1\\\sqrt{x-8} -3+3 = 1+3\\\sqrt{x-8} = 4$

Next we square both sides of the equation to free the unlnown from the square root:

$(\sqrt{x-8})^2 = (4)^2\\x-8=16\\x=16+8\\x=24$

We found x by adding 8 on both sides. Therefore x=24.

One can check the answer by replacing x by 24 in the original equation.

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Solve for all possible values of x. square root of the quantity x minus 8 end quantity minus 3 equals 1

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