Solve for k.
6 (k + 2) +1 = 13

k=0

Step-by-step explanation:

6(k+2)+1=13 first  distribute

6k+12+1=13 then combine like terms

6k+13=13   then subtract 13

    -13   -13

6k=0 then divide 6

/6    /6

k=0

You have already done half of it. Now substitute for x1 = 4 and y = 5
y - 5 = 6/7(x - 4)
Multiply everything by 7 to remove fractions
7y - 35 = 6(x - 4)
7y - 35 = 6x - 24
-6x + 7y = -24 + 35
-6x + 7y = 11

Some people prefer a positive number in front of x so multiply by -1
6x - 7y = -11

You can check the answer by testing it works for both of the original points
6x4 - 7x5 = 24 - 35 = -11 true
6x-3 - 7x-1 = -18 - -7 = -11 true