Solve for n. 2 (4 + n) = 28

n = 10

Step-by-step explanation:

=> 2(4 + n) = 28

=> 2(4) + 2(n) = 28

=> 8 + 2n = 28

=> 2n = 28 - 8

=> 2n = 20

=> n = 20/2

=> n = 10

n = 10

Step-by-step explanation:

2(4 + n) = 28

Distribute:

(8 + 2n) = 28

Eliminate Parenthesis:

8 + 2n = 28

Cancel Out:

2n = 20

Divide:

n = 10

1- Answer B

2- Answer B

1-

Probability of getting a head = .5

Probability of getting a tail = .5

possible outcomes of getting at least one tail = HT, TT, TT

Probability in each of the above cases = .5*.5 +  .5*.5 +  .5*.5 = .75

This will be theoretical probability = .75

as per the question , experimental probability of getting at least one tail =

counting number of outcomes of(HT,TH,TT) ÷ total number of outcomes

experimental probability = (22+34+16) ÷ 100 = .72

So, theoretical probability is 3% greater than experimental probability

2-

You can win only 15 % times.

so, out of 20 games, you can win = 15 % of 20 = 3

so total number of times you can win = 3 times