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erikamaldonado661
06.07.2019 •
Mathematics
Solve for x. 2x2+4x−1=0 enter your answers in the boxes.
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Ответ:
0.2247,-2.2247
Step-by-step explanation:
Equation :![2x^2+4x-1 =0](/tpl/images/0056/6954/007d8.png)
We are supposed to find the values of x .
General form of equation :![ax^2+bx+c=0](/tpl/images/0056/6954/2bf73.png)
Formula :![x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}](/tpl/images/0056/6954/fdf38.png)
a = 2
b = 4
c = -1
So,![x=\frac{-4 \pm \sqrt{4^2-4(2)(-1)}}{2(2)}](/tpl/images/0056/6954/9263a.png)
Hence the values of x are 0.2247,-2.2247
Ответ:
-5x-35<-10
-5x<25
-5x/-5<25/-5
x>-5