jnaifuson
13.08.2020 •
Mathematics
Solve for x: 4x + one half(2x + 4) > 12 x > fourteen fifths x 2 x < 2
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Ответ:
= [sin^2x + 2 sinx cosx + cos^2x] / [2sin^2x-sin^2x-cos^2x]
by simplifying the top to a perfect square binomial youll get (also combine like terms)
= [sinx +cosx]^2 / [sin^2x-cos^2x]
seperate the bottom binomial
= [sinx +cosx]^2 / [(sinx + cosx)(sinx - cosx)]
cancel one (sinx+cosx) from the top and bottom and your answer is
= [sinx +cosx] / [sinx - cosx] which is equal to the left side