jellyangie1
03.12.2020 •
Mathematics
Solve for x.And please show me how u got the answer
9
12
4x - 2)
3x + 2
Solved
Show answers
More tips
- H Health and Medicine These Food Additives Can Do Significant Harm to Your Health...
- F Food and Cooking How to Get Reconfirmation of Registration?...
- C Computers and Internet How to Get Rid of Spam in ICQ?...
- A Art and Culture Who Said The Less We Love a Woman, the More She Likes Us ?...
- F Family and Home How to Get Rid of Your Neighbors?...
- S Society and Politics How Could Nobody Know About the Dead Mountaineers?...
- H Health and Medicine How to Cure Adenoids?...
- H Health and Medicine Why Wearing a Back Brace Can Be Beneficial During Back Strain?...
- S Sport When and Where Will the 2014 World Cup be Held?...
- C Computers and Internet How to Choose a Monitor?...
Answers on questions: Mathematics
- M Mathematics Tennis racket marked up 50% to $36.75.whats the origanal price. my answer was 25.17, which looks to be incorrect....
- B Business Lake Corporation has an activity-based costing system with three activity costs pools- Processing, Supervising, and Other. In the first stage allocations, costs in the...
- C Chemistry Which object would likely have the least amount of wasted energy? a hairdryer a solar cell a car engine a hydroelectric dam...
Ответ:
-7
Step-by-step explanation:
3x + 2 + 12 = 4x -2 + 9
3x + 14 = 4x + 7
-4x -14 -4x -14
-1x = 7
x= -7
Ответ:
a) 132 g NaCl consumed at 1.5 Atm & 290K
b) 93.2 g NaCl consumed at STP
Explanation:
F₂ + 2NaCl => 2NaF + Cl₂
Given 18L F₂(g) at 1.5Atm & 290K
moles F₂(g) = PV/RT = (1.5Atm)(18L)/(0.08206L·Atm/mol·K)(290K) = 1.135 mol F₂(g) consumed
moles NaCl consumed = 2(moles F₂) = 2(1.135) mol NaCl = 2.269 mol NaCl
mass NaCl = 2.269 mol NaCl x 58 g/mol = 131.61 g ≅ 132 g consumed at 1.5 Atm & 290K
Given 18L F₂(g) - same volume as in part a - at STP
moles F₂(g) = PV/RT = (1.0Atm)(18L)/(0.08206L·Atm/mol·K)(273K) = 0.803 mol F₂(g) consumed
moles NaCl consumed = 2(moles F₂) = 2(0.803) mole NaCl = 1.607 mol NaCl
mass NaCl = 1.607 mol NaCl x 58 g/mol = 93.2 g NaCl consumed at STP