Solve for x in the diagram below.
15х – 30°
10x +5°
х = 12
х= 8
х=7
х = 11

range for mr Flore's test = 39

Range for mrs Duncan's test scores = 39

b) Mean of Flore's test scores= 86.7

Mean of Mrs. Duncan's test scores = 81.1

The mean of test scores of mr Flore's test scores is greater than the mean test scores of Mrs. Duncan's.

Step-by-step explanation:

Range is calculated by highest number in a data set - lowest number in a data set

Given the data set for Mr. Flores test scores: 92 87 61 82 98 100 77 64 85 93 92 87 100 93 90

Highest value = 100, lowest value = 61

a) Range for mr. Flore's test = 100 - 61 = 39

Given the data set for Mrs. Duncan's test scores: 82 85 91 76 79 82 95 56 95 89 88 64 69 78 88

ii) Range for mrs Duncan's test score= 95-56= 39

b) mean is calculated by total sum of scores/ number of scores

Mean for mr Flore's test scores = 92 +87 +61 +82 +98 +100 +77 +64 +85+ 93 +92 +87 +100 +93 +90 / 15

=1301/15

=86.7

Mean for mrs. Duncan's test scores = 82 +85 +91 +76+ 79 +82 +95 +56+ 95 +89+ 88+ 64+ 69 +78+ 88 / 15

=1217/15

=81.1

I hope this helps.