Solve for x in the equation x^2+10x+12=36. a. x = –12 or x = 2 b. x = –11 or x = 1 c. x = –2 or x = 12 d. x = –1 or x = 11

Solve for x:
x^2 + 10 x + 12 = 36

36 = 36:
x^2 + 10 x + 12 = 36

Subtract 12 from both sides:
x^2 + 10 x = 24

Add 25 to both sides:
x^2 + 10 x + 25 = 49

Write the left hand side as a square:
(x + 5)^2 = 49

Take the square root of both sides:
x + 5 = 7 or x + 5 = -7

Subtract 5 from both sides:
x = 2 or x + 5 = -7

Subtract 5 from both sides:
  x = 2 or x = -12 Thus the Answer is A.

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