Mathematics: Solve for x in the equation x squared minus 12 x + 59 = 0. x = negative 12 plus-or-minus StartRoot 85 EndRoot x = negative 6 plus-or-minus StartRoot 23 EndRoot i x = 6 plus-or-minus StartRoot 23 EndRoot i x = 12 plus-or-minus StartRoot 85 EndRoot

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Solve for x in the equation x squared minus 12 x

Ответ:

mooncake9090

19.01.2022

Mathematics

Value of x is: $x=6\pm\sqrt{23}i$

Option B is correct option.

Step-by-step explanation:

We need to solve the equation x^2-12x+59=0 and find value of x.

Using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Putting values of a, b and c and finding the value of x

a=1, b=-12 and c=59

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(59)}}{2(1)}\\x=\frac{12\pm\sqrt{144-236}}{2}\\x=\frac{12\pm\sqrt{-92}}{2}\\x=\frac{12\pm\sqrt{92}i}{2}\\We\,\,know\,\sqrt{-1} \,\,is\,\,i\\x=\frac{12\pm2\sqrt{23}i}{2}\\x=\frac{2(6\pm\sqrt{23}i)}{2}\\x=6\pm\sqrt{23}i$

So, value of x is: $x=6\pm\sqrt{23}i$

Option B is correct option.

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Solve for x in the equation x squared minus 12 x + 59 = 0. x = negative 12 plus-or-minus StartRoot 85 EndRoot x = negative 6 plus-or-minus StartRoot 23 EndRoot i x = 6 plus-or-minus StartRoot 23 EndRoot i x = 12 plus-or-minus StartRoot 85 EndRoot

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