Mathematics: Solve for x in the equation x2+20x+100=36

Solve for x in the equation x2+20x+100=36 - id220100361555634, lee9724

Ответ:

nuhaminbruk

15.03.2022

Mathematics

The answer is:
$x = - 64 \div 22 = -2.909091$
But if x2 was supposed to be x^2 then the answer is:
x = - 4.-16

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Ответ:

xelynncaldera

15.03.2022

Mathematics

x = -4 and x = -16.

Step-by-step explanation:

We have the equation,

$x^{2}+20x+100=36$

i.e. $x^{2}+20x+64=0$

As the solution of a quadratic equation $ax^{2}+bx+c=0$ is given by $x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$ .

On comparing, a = 1, b = 20, c = 64.

So, the solution is,

$x=\frac{-20\pm \sqrt{(20)^{2}-4\times 1\times 64}}{2a\times 1}$ .

i.e. $x=\frac{-20\pm \sqrt{400-256}}{2}$ .

i.e. $x=\frac{-20\pm \sqrt{144}}{2}$ .

i.e. $x=\frac{-20\pm 12}{2}$ .

i.e. $x=\frac{-20+12}{2}$ and $x=\frac{-20-12}{2}$ .

i.e. $x=\frac{-8}{2}$ and $x=\frac{-32}{2}$ .

i.e. x = -4 and x = -16

Thus, the solution of the given equation is x = -4 and x = -16.

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Ответ:

bloom826

10.04.2022

Mathematics

250 bottles and 150 bags of trail mix

Step-by-step explanation:

X + y = 400

3.50X + 4y = 1475

x = 400-y

3.50(400-y) + 4y = 1475

1400 - 3.50y + 4y = 1475

1400 +0.50y = 1475

0.50y = 75

y = 75/0.5 = 150

x = 400 - 150 = 250

250 bottles and 150 bags of trail mix

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Solve for x in the equation x2+20x+100=36

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