deadmoney
deadmoney
05.05.2020 • 
Mathematics

Solve for xif 2(5 +252 =48.
0 1= -2+24 and x = =2-324
0 x = -2+4 and x = -2-2V24
e1 = -2+2 and x = =2-2
2
= =2+2V5 and 1 = -2 - 26

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