Solve logx = -3 by changing it to exponential form.
A.x=1/10^3
B.x=-30
C.x=30
D.x=1/3^10

A

Step-by-step explanation:

Using the rule of logarithms

x = n ⇒ x =

Given

x = - 3, then

x = = → A

4

Step-by-step explanation:

You can plug in the b's and see.  You can also try to use a co-function identity and get a value for b that way.

Let's try the co-function identity:

sin(x)=cos(90-x).

First step:

cos(11b+2)=cos(90-[12b-4])

 So one set of solutions can be found by solving:

11b+2=90-[12b-4]

Distribute:

11b+2=90-12b+4

Add 12b on both sides

23b+2=90+4

Simplify:

23b+2=94

Subtract 2 on both sides:

23b     =94-2

23b      =92

Divide both sides by 23:

  b=       92/23

  b=        4

So 4 is one value that will work.