Solve number 11
mathematics
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The volume of a cone is given by the formula: v = (1/3) (area of the base) (height)area of the base = π (radius)^2 = π(4 in)^2 = 16π in^2height = 6 in=> v = (1/3) (π) (4^2)(6) in^3now you have to substract the volume of the gum. the gum is a sphere. the gum of a sphere is: v = (4/3)π(radius)^3 radius = diameter / 2 = 0.8 in / 2 = 0.4 inv = (4/3) π (0.4)^3 in^3therefore the subtraction is: (1/3)π(4^2)(6) in^3 - (4/3)π(0.4)^3 in^3 replacing 3.14 for π: (1/3) (3.14) (4^2)(6) in^3 - (4/3)(3.14)(0.4)^3 in^3that is the second option of your list,except because you forgot to insert the symbol ^ between the number 4 and the number 2, and so it appears to be 42 instead of 4^2.the right answer is with 4^2.final answer: (1/3) (3.14) (4^2)(6) in^3 - (4/3)(3.14)(0.4)^3 in^3