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20.08.2019 •
Mathematics
Solve sint = cos2t, for –4π ≤ t ≤ –2π
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Ответ:
-(23/6)π
-(19/6)π
-3π
Step-by-step explanation:
cos2t=cos^2t-sin^2t => cos^2t=1-sin^2t =>cos2t=1-2sin^2t
sint=1-2sin^2t, if x=sint, thenn we have 2x^2+x-1=0
Here x=0.5, x=-1, as x=sint => sint = -1 solutions for -4π to -2π is t=-3π,
sint = 0.5 solutions for -4π to -2π is t= -(23/6)*π, and t = -(19/6)*π
Ответ: