Solve the following quadratic equation 6x^2-5x-4=0

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

6

2

−

5

−

4

=

0

6x^{2}-5x-4=0

6x2−5x−4=0

=

6

a={\color{#c92786}{6}}

a=6

=

−

5

b={\color{#e8710a}{-5}}

b=−5

=

−

4

c={\color{#129eaf}{-4}}

c=−4

=

−

(

−

5

)

±

(

−

5

)

2

−

4

⋅

6

(

−

4

)

√

2

⋅

6

Step-by-step explanation:

x =

Step-by-step explanation:

Given

5(a - 2x) = 9(x + 1) ← distribute parenthesis on both sides

5a - 10x = 9x + 9 ( add 10x to both sides )

5a = 19x + 9 ( subtract 9 from both sides )

5a - 9 = 19x ( divide both sides by 19 )

= x