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1846252
23.06.2019 •
Mathematics
Solve the inequality and express in interval notation x^2 + 8x + 5 < 0
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Ответ:
Hello from MrBillDoesMath!
x > -4 - sqrt(11) and x < -4 + sqrt(11)
Discussion:
Let's complete the square by adding and subtracting the value 16 from both sides
x^2 + 8x + 5 < 0 =>
(x^2 + 8x + 16) + 5 < 0 + 16 => complete the square
(x + 4) ^2 + 5 < 16 => subtract 5 from both sides
(x+4)^2 < 16 - 5 = 11 => take square root of both sides
(x+4) > -sqrt(11) and ( x+4 ) < sqrt(11) =>
x > -4 - sqrt(11) and x < -4 + sqrt(11)
Thank you,
MrB
Ответ: