abby986
05.09.2020 •
Mathematics
Solve the initial value problem
y′′+4y′+40y=0
y(0)= 3
y′(0)=5.
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Ответ:
The solution is
Step-by-step explanation:
First we will write the characteristic equation, which is
This is a quadratic equation
For the general form of quadratic equation, , is given by the general formula,
or
Hence, for
and
Hence, the formula becomes
or
or
or
or
or
Hence, ±
That is, or
These are the roots of the equation.
For the general solution,
Since the roots of the equation are complex,
If the roots of a characteristic equation are in the form ± , then the general solution is given by
Hence, the general solution for the differential equation becomes
Then
Now, from the question,
y(0)= 3
y′(0)=5.
That is,
∴
[NOTE: and and ]
Also,
Now, we can find by putting the value of into the equation
∴ and
Then the solution becomes
Ответ: