Mathematics: Solve the quadratic equation 5x2 - 125 = 0. x = -5 x = 5 x = ±5 x = ±25

Solve the quadratic equation 5x2 - 125 = 0. x = -5

Ответ:

munozgiselle

04.01.2022

Let's solve this with the quadratic formula, which is: $x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$
Let's plug in the values:
$\frac{-0+\sqrt{0^2-4\cdot \:5\left(-125\right)}}{2\cdot \:5}$
Remove exponents:
$=\frac{-0+\sqrt{0-\left(-125\right)\cdot \:4\cdot \:5}}{2\cdot \:5}$
Simplify.
$=\frac{-0+\sqrt{0-\left(-125\right)\cdot \:4\cdot \:5}}{10}$
$=\frac{\sqrt{-\left(-125\right)\cdot \:20}}{10}$
$=\frac{50}{10}$
$=\pm 5$

This leaves us with the final solutions being:
$x=5,\:x=-5$

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish

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Ответ:

payshencec21

31.08.2022

Mathematics

The length of the rectangle is 10 inches, and the width is 6 inches.

10 + 10 + 6 + 6 = 32

And that's your answer! ^ I hope this helped! c:

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Solve the quadratic equation 5x2 - 125 = 0.
x = -5
x = 5
x = ±5
x = ±25

Ответ:

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