Solve the quadratic equation by completing the square
x² - 8x + 13 = 0

x = 4 ±

Step-by-step explanation:

Given

x² - 8x + 13 = 0 ( subtract 13 from both sides )

x² - 8x = - 13

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 4)x + 16 = - 13 + 16

(x - 4)² = 3 ( take the square root of both sides )

x - 4 = ± ( add 4 to both sides )

x = 4 ±

x = 4 + √3 or x = 4 - √3

Step-by-step explanation:

Use quadratic formula with a=1, b=-8, c=13.

x=−b ± √b2 − 4ac / 2a

x= −(−8) ± √(−8)2 − 4(1)(13) / 2(1)

x= 8 ± √12 / 2

x= 4 + √3 or x= 4 − √3

See explanation below.

Step-by-step explanation:

Part A:

(i). They both correct because they could have a third degree polynomial that crosses the x-axis 3 times.

(ii). To find the zero's of the first one, set function equal to zero and use zero factor principle given as:

So, we have: