Solve the system 2y+8x+58 and y-5x=11

x=2, y=21

Step-by-step explanation:

there are two methods: substiution and elimation. I will be doing subtistution in this soultion:

first isolate y in either equation, it would be easier to do it in the second one.

y= 11+5x

Then, subtitute that into the first equation

2(11+5x)+8x=58 (it says 2y+8x+58 but I assume you mean 2y+8x=58?)

22+10x+8x=58

18x = 36

x=2

substitute that back into y = 11+5x, to get y=11+10 = 21

20(5) + 5(20) + 95.50 = money in account100 + 100 + 95.50 = $295.5Part B = $295.5If Marla's mom deposited $10 after each car wash the coefficient would change.20c+5w+95.50 - the 20 beside the c is the coefficient and the 95.50 is the constant. A coefficient is the number being multiplied to the variable. In this case c is the variable and 20 is the coefficient. Therefore the constant would change.Part C = If Marla's mom deposited $10 after each car wash the coefficient would change.