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Juancr4539
25.03.2020 •
Mathematics
Solve the system of equations 2x+4y+3z=6 5x+8y+6z=4
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Ответ:
Solution :
{x,y,z} = {-8,52/7,-18/7}
System of Linear Equations entered :
[1] 2x + 4y + 3z = 6
[2] 5x + 8y + 6z = 4
[3] 4x + 5y + 2z = 0
Solve by Substitution :
// Solve equation [3] for the variable z
[3] 2z = -4x - 5y
[3] z = -2x - 5y/2
// Plug this in for variable z in equation [1]
[1] 2x + 4y + 3•(-2x-5y/2) = 6
[1] -4x - 7y/2 = 6
[1] -8x - 7y = 12
// Plug this in for variable z in equation [2]
[2] 5x + 8y + 6•(-2x-5y/2) = 4
[2] -7x - 7y = 4
// Solve equation [2] for the variable y
[2] 7y = -7x - 4
[2] y = -x - 4/7
// Plug this in for variable y in equation [1]
[1] -8x - 7•(-x -4/7) = 12
[1] -x = 8
// Solve equation [1] for the variable x
[1] x = - 8
// By now we know this much :
x = -8
y = -x-4/7
z = -2x-5y/2
// Use the x value to solve for y
y = -(-8)-4/7 = 52/7
// Use the x and y values to solve for z
z = -2(-8)-(5/2)(52/7) = -18/7
Solution :
{x,y,z} = {-8,52/7,-18/7}
Step-by-step explanation:
Ответ:
The answer is B
Step-by-step explanation:
Ответ:
b>1