solve the system using substitution.
-3x+y=10
-6x+2y=20

no solutions

(–3, 2)

infinite solutions

(3, 0)

The correct answer is infinite solutions

Step-by-step explanation:

It is given that,

-3x+y=10     (1)

-6x+2y=20  (2)

eq (1) x 2 ⇒ -6x+2y=20  (3)

from this we get eq(2) and eq(3) are same.

Therefore these two equation have infinite solution.

To find the solution using substitution

-3x+y=10     (1)

y = 3x +10

Substitute the value of y in eq(2)

-6x+2y=20  (2)

-6x +2(3x +10) = 20

-6x + 6x + 20 = 20

20 = 20