Solve this indices a²b + a³b / a²b²

Step-by-step explanation:

Notice: The literal factors are all the combinations of a and b where the sum of the exponents is 4: a4, a³b, a²b², ab³, b4 ... The solution to the problem of the binomial coefficients without actually ... The upper index n is the exponent of the expansion; the lower index k indicates which term ... 1a5 + a4b + a3b² + a²b3 + ab4 + b5.

The answer is B.   Because there are 8 ribbons in all. 1 ribbon is black. so the equation would be 1/8. Assuming you don't draw the black ribbon on the first try, then you would try again. The second time you draw a ribbon you don't put the ribbon you drew back in. That means there are only 7 ribbons the second time. The 1 black ribbon is still in the bag than the equation would be 1/7. Then you add the two together. So it would be 1/8 + 1/7 = 1/15. Remember to only add the bottom numbers. not the top ones unless they are different colors or objects.