Solve this quadratic equation using the quadratic formula.
5 - 10x - 3x2 = 0

-3x^2 - 10x + 5 = 0

Quadratic formula:

-b +/- sqrt[b^2 - 4(a)(c)]/2(a)

So. . . 10 +/- sqrt[(10^2) - 4(-3)(5)]/2(-3)

10 +/- sqrt[100+60]/ -6

10 +/- sqrt[160]/-6

The correct option is;

They form concentric circles

Step-by-step explanation:

Given that the coordinates of the vertices of the trapezoid are;

E = (-4, 8)

F = (-7, 5)

G = (-4, 3)

H = (-2, 5)

We note that the distances from the origin, O, to the vertices are;

OE = √((-4)² + 8²) = √(80) = 4·√5

OF = √((-7)² + 5²) = √(74)

OG = √((-4)² + 3²) = √(25) = 5

OH = = √((-2)² + 5²) = √(29)

When rotated 720° about the origin, each point behaves as the radius of a circle with center at the origin such that they form concentric circles with OE being the largest circle and OG the smallest circle at the center.