Solve with completing the square method: 6x²-7x+2=0

Ответ:

dugg5361

31.12.2021

$6x ^2-7x+2=0\\ \\ a=6 , \ b = -7 , \ c=2 \\ \\\Delta = b^{2}-4ac = (-7)^{2}-4*6*2=49-48=1 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{7-\sqrt{1}}{2*6}=\frac{7-1}{12} =\frac{6}{12}= \frac{1}{ 2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{7+\sqrt{1}}{2*6}=\frac{7+1}{12} =\frac{8}{12}= \frac{2}{ 3}$

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Ответ:

shaheedbrown06

15.05.2021

Mathematics

2/5x >= 1/5 multiple both sides by 5/2
so , x >= 1/2

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Solve with completing the square method:
6x²-7x+2=0 and ax²+bx+c=0

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Solve with completing the square method: 6x²-7x+2=0 and ax²+bx+c=0

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Solve with completing the square method:
6x²-7x+2=0 and ax²+bx+c=0