Mathematics: Solve x^2- 2x - 4 = 0

Solve x^2- 2x - 4 = 0 - id224010135986, liv696

Ответ:

FailingstudentXD

16.03.2022

Mathematics

$\displaystyle x= 1\pm \sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Standard Form: ax² + bx + c = 0Quadratic Formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1: Define

x² - 2x - 4 = 0

Step 2: Identify Variables

a = 1

b = -2

c = -4

Step 3: Solve for x

Substitute [QF]: $\displaystyle x=\frac{2\pm\sqrt{(-2)^2-4(1)(-4)} }{2(1)}$ Exponents: $\displaystyle x=\frac{2\pm\sqrt{4-4(1)(-4)} }{2(1)}$ Multiply: $\displaystyle x=\frac{2\pm\sqrt{4+16} }{2}$ Add: $\displaystyle x=\frac{2\pm\sqrt{20} }{2}$ Simplify: $\displaystyle x=\frac{2\pm 2\sqrt{5} }{2}$ Factor: $\displaystyle x=\frac{2(1\pm \sqrt{5}) }{2}$ Divide: $\displaystyle x= 1\pm \sqrt{5}$

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Ответ:

oliup567

15.02.2020

Mathematics

Graph one: Not a function

Graph two: Function

Graph three: this looks like a function picture isn't clear on my end

Step-by-step explanation:

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Solve x^2- 2x - 4 = 0

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