janeou17xn
24.09.2019 •
Mathematics
Solve x^2 +4-4=8 for x
x=-6 or x=2
x=-2+/- 2 (square root) 2
x=-2 or x =6
x=2+/-2 (square root)2
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Ответ:
x² +4x -12 =0
(x+6)(x-2) = 0
x+6 =0 or x-2 = 0
x = -6 or x = 2 ( first answer )
Ответ:
1.
7x+11y-(5x+6y)
7x+11y-5x-6y
2x+5y
2.
13x+12y-(6x+2y)
13x+12y-6x-2y
7x+10y
3.
8x+8y-(4x-2y)
8x+8y-4x+8y
4x+16y
Let me know if this helps!