Solve x^2 + 6x + 7 = 0. If you are going to comment in here please know the answer, this is so serious for me. Thank you.

Third option

Step-by-step explanation:

We can't factor this so we need to use the quadratic formula which states that when ax² + bx + c = 0, x = (-b ± √(b² - 4ac)) / 2a. However, we notice that b (which is 6) is even, so we can use the special quadratic formula which states that when ax² + bx + c = 0 and b is even, x = (-b' ± √(b'² - ac)) / a where b' = b / 2. In this case, a = 1, b' = 3 and c = 7 so:

x = (-3 ± √(3² - 1 * 7)) / 1 = -3 ± √2

A = pi * r^2

 = pi * (2x^-3)^2

 = pi * 2^2 * (x^-3)^2

 = pi * 4 * (x^-6)

 = 4*pi * x^-6